L'esempio che usando la c che si programma assegna dinamicamente un allineamento delle strutture per immagazzinare i nomi ed il grado dell'allievo. I gradi allora sono visualizzati di nuovo all'utente nell'ordine ascendente.

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Il seguente esempio assegna dinamicamente un allineamento delle strutture per immagazzinare i nomi ed il grado degli allievi. I gradi allora sono visualizzati di nuovo all'utente nell'ordine ascendente.

#include <string.h>
#include <malloc.h>

struct student
{
char *name;
int grade;
};

void swap(struct student *x, struct student *y);

int main()
{
struct student *group;
char buffer[80];
int spurious;
int inner, outer;
int counter, numStudents;

printf("How many students are there in the group: ");
scanf("%d", &numStudents);

group = (struct student *)malloc(numStudents *
sizeof(struct student));

for (counter=0; counter<numStudents; counter++)
{
spurious = getchar();

printf("Enter the name of the student: ");
gets(buffer);
group[counter].name = (char *)malloc((strlen(buffer)+1) * sizeof(char));
strcpy(group[counter].name, buffer);

printf("Enter grade: ");
scanf("%d", &group[counter].grade);
}

for (outer=0; outer<numStudents; outer++)
for (inner=0; inner<outer; inner++)
if (group[outer].grade <
group[inner].grade)

swap(&group[outer], &group[inner]);

puts("The group in ascending order of grades ...");

for (counter=0; counter<numStudents; counter++)

printf("%s achieved Grade %d \n”,
group[counter].name,
group[counter].grade);

return 0;
}

void swap(struct student *x, struct student *y)
{
struct student temp;

temp.name = (char *)malloc((strlen(x->name)+1) *
sizeof(char));

strcpy(temp.name, x->name);
temp.grade = x->grade;

x->grade = y->grade;
x->name = (char *)malloc((strlen(y->name)+1) *
sizeof(char));
strcpy(x->name, y->name);
y->grade = temp.grade;
y->name = (char *)malloc((strlen(temp.name)+1) *
sizeof(char));
strcpy(y->name, temp.name);
}

 

L'esecuzione dell'uscita sarà come segue:

How many students are there in the group: 4
Enter the name of the student: Anuraaj
Enter grade: 7
Enter the name of the student: Honey
Enter grade: 2
Enter the name of the student: Meetushi
Enter grade: 1
Enter the name of the student: Deepti
Enter grade: 4
The group in ascending order of grades ...

Meetushi achieved Grade 1
Honey achieved Grade 2
Deepti achieved Grade 4
Anuraaj achieved Grade 7

 

Sample Chapters from book DATA RECOVERY WITH AND WITHOUT PROGRAMMING by Author Tarun Tyagi
Data Recovery with & without Programming


Publishers of the Book
Number of Pages
ISBN
Price of the Book


BPB Publications, New Delhi, India
540
81-7656-922-4
$69.00 (Including Shipping Charges, Cost of Book and Other expenses, Free Source Code CD included with the Book)





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